Calcular el área de los siguientes triángulos

C= a+b
C= 27.5+36.5 sen b = 36.5/45.7 = 53°
C=756.25+1332.25 cos b = 27.5/45.7 = 53°
C=2088.5 tg = 36.5/27.5 = 53°
C=45.7

A= c-b
A=30-15 sen a= 25.9/30 = 59° 41
A=900-225 cos a = 15/30 = 60° 0
A= 675 tg = 25.9/15 = 59° 55
A= 25.9

B=c-a
B= 5-3 sen b = 4/5 = 53° 7
B=25-9 cos b = 3/5 = 53° 7
B=16 tg b= 4/5= 53° 7
B= 4

C= a+b
C=13.5+21.7 sen a =13.5/25.5 = 31° 57
C=182.25+470.89 cos a = 21.7/25.5 = 31° 40
C= 653.14 tg= 13.5/21.7 = 31° 53
C= 25.5

C= a+b sen a = 9.17/94= 5° 35
C=9.17+3.15 cos a = 3.15/94 = 88° 4
C=84.0889+9.9225 tg a=9.17/3.15 = 71° 2
C= 94

B=c-a
B=3.5-2.3 sen b =2.6/3.5=47° 58
B=12.25-5.29 cos b= 2.3/3.5 = 48° 55
B=6.96 tg =2.6/2.3 = 48° 30
B=2.6

c=a+b
c=37.96+41.80 sen c = 37.96/56.46= 42° 14
c= 1440.9616+1747.24 cos = 41.80/56.46 = 42° 14
c= 1625.67 tg a = 37.96/41.80 = 42° 14
c= 40.31

A= c-b
A=45.6-21.3 sen a = 21.3/45.6 =27° 50
A=2079.36-453.69 cos a = 40.31/45.6 = 27° 52
A= 1625.67 tg a = 21.3/40.31 = 27° 51
A=40.31